Let f be a continuous function on the closed interval [0,2]. If 2≤ f(x)≤ 4, then the greatest possible value of : ∫(0 to 2) f(x)dx is:

Question

A) 0

B) 2

C) 4

D) 8

E) 16

Answer 1

∫₀²f(x)dx ≤ ∫₀²4dx = 4x₀² = 8

Answer: D).