Nine times the sum of a number and 8 is equal to 3

Answer 1

Let "n" be a number. Then the sum of a number and 8 is "n + 8" and nine times that is "9(n + 8)" so

9(n + 8) = 3

To solve, divide both sides by 9 to get:

n + 8 = 3/9

n + 8 = 1/3

Now subtract 8 from both sides to get:

n = 1/3 - 8

n = 1/3 - 24/3

n = -23/3