b. The set is linearly independent if and only if the only values of A, B, C in the equation
Af1 + Bf2 + Cf3 = 0t2 + 0t + 0 are A = B = C = 0.
We have A(2t - 3) + B(t2 + 1) + C(2t2 - t) = 0t2 + 0t + 0
Equating coefficients of like powers, we get B + 2C = 0, 2A - C = 0 and -3A + B = 0
From the second equation, C = 2A.
Replace C by 2A in the equation B + 2C = 0 to get B = -4A.
So, since B = -4A and -3A + B = 0, we have -7A = 0.
Thus, A = 0, B = -4A = 0, and C = 2A = 0
Therefore, the set is linearly independent.
a. The set of all second degree polynomials (in the variable t) with real coefficients is a 3-dimensional vector space with basis {1, t, t2}. Since any subset of a 3-dimensional vector space that contains more than 3 elements is linearly dependent, the given set is NOT linearly independent.