Solve for the general solution of the differential equation ((2D-1)^2)y=0

Answer 1

When you multiply the (2D-1)2 term, you obtain 4D2 - 4D + 1 = 0

Which should be 4d²y/dx² - 4dy/dx + 1 = 0

or d²y/dx² - dy/dx + 1/4 = 0

This should be no problem to solve but needs and initial condition to complete the problem!