Use parametric differentiation to find dy/dx for the curve defined by the equations

Question

x = -68t^2 + 2t - 19

y = 6e^t

Answer 1

x = - 68t² + 2t - 19, y = 6e^t; dy/dx = (dy/dt)/(dx/dt) = (6e^t)/(- 136t + 2) = 3e^t/(1 - 68t)