Hello, Kj,
The balanced equation tells us we get 2 moles of product for every 3 moles of O2. If we assume that there is more than enough aluminum as a reactant, the moles of product can be found by the taking product of moles O2 (49.2 moles in this case) and the molar ratio of (2 moles Al2O3/(3 moles O2).
49.2 moles * 2/3 = moles Al2O3 produced. (32.8 moles)
Bob