How to write parabola equation in standard form with x intercepts (-3,0) and (1,0) with vertex (-1,-3)

Answer 1

y=a(x+1)^2 -3

in vertex form

then plug in the point (-3,0) to find the coefficient

0=a(-3+1)^2 -3

3=4a

a= 3/4

y=(3/4)(x+1)^2-3