
Yefim S. answered 07/18/20
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f(t) = sin(5t)cos6 + cos(5t)sin6.
So L{f(t)} = cos6·5/(s2 + 25) + sin6·s/(s2 + 25)= (5cos6 + s·sin6)/(s2 + 25)·
Ibr A.
asked 07/18/20Find ℒ{f(t)}
by first using a trigonometric identity. (Write your answer as a function of s.)
f(t) = sin(5t + 6)
Yefim S. answered 07/18/20
Math Tutor with Experience
f(t) = sin(5t)cos6 + cos(5t)sin6.
So L{f(t)} = cos6·5/(s2 + 25) + sin6·s/(s2 + 25)= (5cos6 + s·sin6)/(s2 + 25)·
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