
Yefim S. answered 07/11/20
Math Tutor with Experience
Let found fundamental solutions of homoginius equationsoluyion: y'' - y = 0,
Characteristic equation: r2 - 1 = 0, r = ±1, y1 = ex, y2 = e-x.
Wronscian W = det[(ex, ex) (e-x, - e-x) = - 2,
So, yp = - ex·∫e-x(ex/(ex + e-x))/(-2)dx + e-x·∫ex(ex/(ex + e-x))/(-2)dx = 1/2extan-1(ex) -1/2e-x(ex - tan-1(ex)) =
1/2(ex + e-x)tan-1(ex) - 1/2