
Yefim S. answered 07/09/20
Math Tutor with Experience
Characteristic equation here is: r4 + 8r2 + 16 = 0; (r2 + 4)2 = 0, r2 + 4 = 0, r2 = - 4, r = ±2i.
So we have 4 imaginary zeros 2i, 2i, - 2i - 2i.
Because general solution for this equation: y = (C1x + C2)cos(2x) + (C3x + C4)sin(2x).
Here C1, C2,C3, C4 are arbitrary constants.