
Yefim S. answered 03/09/21
Math Tutor with Experience
This is exact equation, because ∂/∂y(x + tan-1y) = ∂/∂x((x + y)/(y2 + 1) = 1/(1 + y2);
F(x,y) = ∫(x + tan-1y)dx = x2/2 + xtan-1y + φ(y);
∂F/∂y = x/(1 + y2) + φ'(y) = (x + y)/(1 + y2); φ'(y) = y/(1 + y2); φ(y) = ∫y/(1+ y2)dy = 1/2ln(1 +, y2) + C;
F(x,y) = x2/2 + xtan-1y + 1/2ln(1 + y2) + C.