
Yefim S. answered 07/06/20
Math Tutor with Experience
Let m is m of solt at time t, then dm/dt = - 3m/(v0 + 4t), At t = 0 m = m0 and v0 + 4t = v. We separate variables:
dm/m = - -3dt/(v0 + 4t). So, lnm = - 3/4 ln(v0 + 4t) + lnC, m = C(v0 + 4t)- 3/4. m0 = Cv0-3/4.
Now 120 = 40 + 4t, so t = 20 min. m = C(120)-3/4 = 11, C = 11·1203/4 = 398.82
For mass of solt we have now m = 398.82·(v0 + 4t)-3/4. If t = 0 m0 = 398.82·v0-3/4 = 398.82/403/4 = 25.87 kg .