Provide a synthesis

Question

Draw the predominant forms of aspartic acid at ph of 7 and 14

Answer 1

pH = 7:

COO- (-) CH (-) CH2 (-) COO-

(-)

NH3+

pH = 14:

COO- (-) CH (-) CH2 (-) COO-

(-)

NH2

(-) represents a single bond.

The increase in pH for 7 to 14 indicates a "decrease" in acidity (ideally more OH- ions), therefore a hydrogen is removed from the NH3+ group.

For comparison aspartic acid at pH = 1 would be:

COOH (-) CH (-) CH2 (-) COOH

(-)

NH3+

Where available electron pairs on the oxygen atoms are bound by H+ ions due to the increase acidity.