How to graph y <or= 3/2x+3 , -y<2x

Question

Describe and correct the error graphing this system of inequalities 

 

y<or= 3/2x+3

-y<2x

Answer 1

Hi Hannah,

 

1) ignore the inequality to start with

2) Make sure to draw a solid line because you have </= to....

3) test the inequality after you have finished drawing the line (use (0,0) whenever possible. It's the simplest).

 

y=3/2x + 3

 

I can't, of course, draw the graph for you but I can help you test which region

 

0</=3/2(0) + 3

0</=3------------------------------ is true. Therefore, the half that includes the origin (0,0) is the part thet you would shade as the area of solution

I hope this helps