The series does not pass the divergence test: Limit as n goes to infinity of an must go to 0 for convergent series.
The first term does qualify(although it is the harmonic series and you can show divergence by the integral test: ∫ 1∞ 1/x dx diverges) , but the second term grows with n and cos2(n) has a value between 0 and 1. Even if the first series converged (which it doesn't) you are adding a divergent series to it. Another way to say it is that an doesn't have a limit at all because the cos function does not approach a limit. Even if the 1st series converged and the second term was just cos2n, the series would still diverge!