Raymond B. answered • 05/04/20
Tutor
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Math, microeconomics or criminal justice
Multiply both fractions by (x-3)(x+4)
to get
6(x+4) - 8(x-3) all over the denominator (x-3)(x+4)
expand and combine like terms
6x+24 -8x +24 = -2x+48 = 2(-x+14)
You might want to factor out a 2, and rearrange terms to eliminate the negative sign, getting
a final fraction of
2(24-x)/(x-3)(x+4)
in the original two fractions or the combined single fraction the restrictions
are no denominator can be zero. That excludes x as 3 or -4
David M.
In the expansion you made an error in that 6(x+4)=6x+24, not 6x+4.05/04/20