
Jesse E. answered 05/03/20
Experienced Biochemistry Tutor
We will use the Henderson Hasselbalch Equation:
pH - pKa + log(B/A)
Ka of acetic acid (Ch3CO2H) is 1.8 x 10-5)
Let's first determine the pKa:
pKa = -log(1.8 x 10-5) = 4.74
Now let's look at amounts of weak acids and conjugate bases. Comparing 0.195 WA to 0.125 WB, we see that we have a higher amount of WA. This means that we should have a more acidic buffer, which is indicated a pH lower than the pKa. Let us see if this works.
pH = -log(1.8 x 10-5) + log(0.125 M/0.195) = 4.55
Yes. This checks out so the buffer is 4.55.