select the approximate values of x that are solutions to f(x)=0, where f(x)=-3x^2+3x+3

Question

Need help finding this solution :)

Answer 1

f(x)= -3x^2 + 3x + 3

 

-3x^2 + 3x + 3 = 0

 

Divide through by -3 to simplify the equation and get

 

x^2 - x - 1 = 0

 

Use the quadratic formula:

 

x = {-(-1) ± √[(-1)^2 - 4(-1)]} / 2

 

x = (1 ± √5) / 2

 

These are your two solutions, both real.