
Yefim S. answered 02/13/20
Math Tutor with Experience
Let differentiate both sides: y' + xy'' - y' = ey'y'', or xy" - y''ey' = 0; y''(x - ey') = 0.
These differential equation we can spleet on 2 equations: y'' = 0 and x - ey'= 0.
From first equation we have y' = C. Let put this in differential equation: x·C - y = eC , y = Cx - eC;
Now we solve second equation: x = ey', y' = lnx; y = ∫lnxdx, y = xlnx - x + C. Thiks function satisfy given equation if C = 0.
Answer: y = C x - eC and y = xlnx - x solutions of given equation