Based on percentages In chemistry

Question

An alloy contains 58g of pure and 21g of pure copper.what is the percentage silver in the alloy?

Answer 1

Hi Harriet L.,

The percentage of silver, in a silver-gold alloy is equal to the mass of the silver in the alloy divided by the mass of the alloy times 100, (grams silver / grams alloy)*100.

The mass of the alloy is 58 g silver + 21 g copper = 79 g alloy.

The percentage of silver in the alloy is:

(58 g / 79 g)*100 = 0.734*100 = 73%.

I hope this helps, Joe.