
Sanjay S. answered 01/19/15
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Bailey,
Assume Mr. Adrian has been teaching for A years, Ms. Betty for B years and Mr. Charlie for C years
A + B = 36
B + C = 22
A + C = 28
You have 3 equations in 3 unknowns which can be solved in multiple ways.
Adding all 3 equations
2A + 2B + 2C = 86
A + B + C = 43
This is your new eq.
Subtract first eq. from the new eq, C = 7
Subtract second eq from the new eq , A = 21
Subtract third eq. from the new eq: B = 15
This gives you the number of years each has taught.