equation of circle

Question

find the coordinates of the center of the circle given by the equation 3x^2 +3y^2-12x-6y=15.

Step by step

thanks

Answer 1

Equation of circle: (x-h)² + (y-k)² = r². (h,k) is the center and r is the radius.

3x² - 12x + 3y² - 6y = 15

Divide by 3:

(x² - 4x) + (y² - 2y) = 5

Complete the square inside each pair of parentheses:

(x² - 4x + 4) + (y² - 2y + 1) = 5 + 4 + 1

(x - 2)² + (y - 1)² = 10

center = (2,1) and radius = √10