Inactive Tutor answered 06/27/19
Using the Trapezoidal Rule, the area is approximately
[1/2 (f(0) + 2f(1/2) + 2f(1) + 2f(3/2) + f(2))]*(1/2)
1/4 (0 + 3/2 + 6 + 27/2 + 12)
= 1/4 (33)
= 33/4 = 8.25
The actual area is ∫02 3x^2 dx = x^3 |02 = 8
Cool G.
asked 06/21/19Approximate the value of the given integra
(a) Use the trapezoidal rule, using
n=4.
(b) Check by direct integration.
Integral from 0 to 2 3x^2 dx
Inactive Tutor answered 06/27/19
Using the Trapezoidal Rule, the area is approximately
[1/2 (f(0) + 2f(1/2) + 2f(1) + 2f(3/2) + f(2))]*(1/2)
1/4 (0 + 3/2 + 6 + 27/2 + 12)
= 1/4 (33)
= 33/4 = 8.25
The actual area is ∫02 3x^2 dx = x^3 |02 = 8
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