Find the equation of the tangent line that passes through the point. f (t) = t^2 - 6 t - 1, (2, -3)?

Answer 1

f'(t) =2t-6 so the slope is m= 2•2-6= -2 the tangent line can be found using the straight line equation y=mx+b. In so doing -3 = -2•2 +b and b= -3 +4 =1 so the tangent line at (2,-3) is f(t) = -2t+ 1