Find the differential equations: 8y'' + 10y' - 3y = 0?

Answer 1

If you rearrange the equation to y'' + (5/4)y' - (3/8) = 0

The solution to the characteristic equation is 1/4 and -3/2

So, The general equation is y = C₁e^(x/4) + C₂e^(-3x/2)

^{(Where C}₁ ^{and C}₂ ^{are constants)}