If y = -5x/(x+1). Then the derivative is -5/(x+1)^2. Which is the slope of the tangent line.
So, at the point x = 1, dy/dx = -5/4
Therefore, the equation of the tangent line is.... y+5/2 = -5/4(x-1)
or, y = (-5/4)x - 5/4
If y = -5x/(x+1). Then the derivative is -5/(x+1)^2. Which is the slope of the tangent line.
So, at the point x = 1, dy/dx = -5/4
Therefore, the equation of the tangent line is.... y+5/2 = -5/4(x-1)
or, y = (-5/4)x - 5/4
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