Evaluate the iterated integral first from 0 to 3 then from 0 to 1 of (x+y^2) dy dx?

Answer 1

If I am reading the integration correctly, the problem is {₀¹{₀³ (x + y²)dydx

Integrating {₀¹ (xy + y³/3)₀³ = {₀¹ (3x + 9) dx = ((3/2)x² + 9x)₀¹ = 3/2 + 9 = 21/2