A stock solution of HNO3 is prepared and found to contain 12.0 M of HNO3.

Question

If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is ________ M.

1.67

240

0.600

600

0.240

Answer 1

We use the following equation to find the concentration of the diluted solution:

M₁V₁ = M₂V₂

where M₁V₁ refers to the concentration and volume of the initial solution, respectively, and M₂V₂ refers to the concentration and volume of the final solution, respectively.

In this case, we are trying to find the final concentartion, M₂:

M_{2 =} M₁V_1/V₂ = (12.0 M * 0.025 L)/ 0.500 L) = 0.6 M