Create the equation of the line that is perpendicular.

Question

Create a line perpendicular to the line that goes between the points (-7,0) and (0,13)

Answer 1

first find the line that goes through (-7,0) and (0,13)

y=mx+b

m=(13-0)/[0-(-7)]

m=13/7

y=(13/7)x+b

use either point to find b

13=(13/7)(0)+b

13=0+b

b=13

the line is y=(13/7)x+13

a line perpendicular to this line will have a slope that is the negative reciprocal of 13/7

one such line is y=(-7/13)x+13