Arthur D. answered • 12/15/14

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first find the line that goes through (-7,0) and (0,13)

y=mx+b

m=(13-0)/[0-(-7)]

m=13/7

y=(13/7)x+b

use either point to find b

13=(13/7)(0)+b

13=0+b

b=13

the line is y=(13/7)x+13

a line perpendicular to this line will have a slope that is the negative reciprocal of 13/7

one such line is y=(-7/13)x+13