What is the equation of the line tangent to the circle of x^2+y^2=25 at the point (3, -4)?

Answer 1

The line from the center of the circle to the point (3,-4) is y = (-4/3)x

The slope of the tangent line (perpendicular) is 3/4 (Slope Equals -1/ (-4/3) )

So the tangent line form is y - (-4) = (3/4)(x - 3) or y = (3/4)x -25/4