What is the equation of the line tangent to the circle of x^2+y^2=29 at the point (2, -5)?

Answer 1

The radius from the origin to the point (2,-5) is y = (-5/2)x any perpendicular line (or tangent line) then

must have a slope of -1/(-5/2) = 2/5, So the equation of the tangent line is found as

y-y₁ = m (x-x₁) 0r y+5 = (2/5)(x-2) rearranging we find that y = (2/5)x - 29/5