There were no initial conditions given? Assuming f(0) = A and f'(0) = B
1) You could use numerical analysis methods to solve
2) You could obtain a series solution using Taylor's series for example.
f(x) = f(0) + f'(0)x + f"(0)x2/2! + f"'(0)x3/3! + ..............................
or f(x) = A + Bx + ((aA+cB)/A)x2/2 + ((acA+c2B-c2B2)/A2)x3/6 + .....................
the higher order derivatives may be cumbersome and the series may converge slowly but it is a valid solution and Taylor's series do converge!