Is (1,-2,0) a solution to the system?

Question

3x+y+4z=1

x-y+z+-1

2x+y+3z=0

Answer 1

The solution is in the form (x,y,z).  In this case, x = 1, y = -2, and z = 0.

When you plug the values for each variable into the right spots in each equation they will either check out or they will not.  

 

If all 3 equations check out, the the provided answer is a solution to the system of equations.

If even one equation doesn't check out, then the given answer is not a solution to the system.

Answer 2

3(1) + (-2) + 4(0) =1 ...3 -2 +0 = 1... 3-2= 1...yes for the 1st

     the second  doesn't have a equal sigh so i can't give a answer either way there

  2(1) + (-2) + 3(0) = 0...   2-2+0 =0 ...2-2= 0 ...yes .

       Yes for the first and third and i don't know for the second since the equation doesn't have something to equal to