Organic Chemistry Help!

Question

Write the structural formula and name of the organic product for the following reaction between an alkyne and an alkyl halide. (The alkyne group is shown, and should be entered, as "CC", without the triple bond.)

 

             1. NaNH₂

CH₃CCH -------->

             2. CH₃Br

 

(a) Product structural formula (formatting counts: enter C before associated H atoms; subscript numbers) (e.g., CH₃CH₂CH₂OCHCHCH₃):

 

(b) Product name:

Answer 1

A) In the first part of the reaction, the NaNH₂ will act as a nucleophile, attacking the hydrogen on the triple bond and deprotonating the alkyne, yielding NH3 + CH3CC- (Alkyne carbanion) Na+

The CH₃CC^- will then act as a nucleophile, attacking the CH₃Br and forcing the Br group to leave as an anion (Br-). This leaves the final product of CH₃CCCH₃  + Br^- NA⁺ + NH₃

 

 

Answer 2

CH₃CCCH₃

 

2-Propyne