
Lucio F. answered 04/05/19
Physical Chemistry MS+PhD (UC San Diego) + Post-doc (UC Berkeley)
1. n-Butylalcohol = CH3CH2CH2CH2OH = 1° alcohol (primary alcohol)
2. sec-Butyl alcohol = CH3CH(OH)CH2CH3 = 2° alcohol (secondary alcohol)
3. tert-Butyl alcohol = (CH3)3COH = 3° alcohol (tertiary alcohol)
The more exposed the hydroxyl group is to other hydroxyl groups, the more it can participate in hydrogen bonding and increase its boiling point. The boiling points go as 1°>2°>3°.