
Mark W. answered 11/13/14
Tutor
4
(1)
Former Air Force Officer / Certified (SC, TX) HS Math Teacher
Let's let v be the speed of the slower car. Then, v + 25 is the speed of the faster one.
Dimensionally, speed is distance divided by time. Distance divided by speed is distance divided by (distance divided by time), so distance divided by speed is time. The two vehicles traveled different distances in the same time, so our equation then looks like this:
225/v = 325/(v+25)
Cross-multiplying to clear the denominators, we get:
225v + 5625 = 325v
Subtracting 225v from both sides, we get:
Dimensionally, speed is distance divided by time. Distance divided by speed is distance divided by (distance divided by time), so distance divided by speed is time. The two vehicles traveled different distances in the same time, so our equation then looks like this:
225/v = 325/(v+25)
Cross-multiplying to clear the denominators, we get:
225v + 5625 = 325v
Subtracting 225v from both sides, we get:
5625 = 100v
Dividing by 100, we get
56.25 = v
Plugging that back in, we see that the slower car does 225 km in 4 hours, and the faster car, driving at 81.25 km/hr, goes 325 km in 4 hours - it works.
Dividing by 100, we get
56.25 = v
Plugging that back in, we see that the slower car does 225 km in 4 hours, and the faster car, driving at 81.25 km/hr, goes 325 km in 4 hours - it works.