
Nietu P. answered 11/05/14
Tutor
5
(1)
I bet your kid is going to love math.
1) 2x+12/(x+6)(2x+1)
1st - determine non-permissible values
Take the denominator and make it equal zero
(x+6)(2x+1)=0
(x+6)(2x+1)=0
x+6=0 ; 2x+1 = 0
x= -6 ; 2x =-1
; x=-1/2
Non-permissible values are x ≠ -6, -1/2
2nd - look to cancel out equivalent expression
2(x+6)/(x+6)(2x+1)
2(x+6)/(x+6)(2x+1)
2/(2x+1)
Final answer : 2/(2x+1) ; x ≠ -6, -1/2
2) 14-2n/n²-7n
1st - determine non-permissible values
Take the denominator and make it equal zero
n²-7n = 0
Take the denominator and make it equal zero
n²-7n = 0
n(n-7) = 0
n=0 ; n-7 = 0
; n=7
Non-permissible values are n ≠ 0, 7
2nd - look to cancel out equivalent expression
2nd - look to cancel out equivalent expression
14-2n/n²-7n
2 (7-n) /n (n-7)
- 2 (n-7) /n (n-7)
- 2 (n-7) /n (n-7)
-2/n
Final answer : -2/n ; n ≠ 0, 7
3) 6y²+9y/12y²
1st - determine non-permissible values
Take the denominator and make it equal zero
1st - determine non-permissible values
Take the denominator and make it equal zero
12y² = 0
y² = 0
y = 0
Non-permissible values are y ≠ 0
2nd - look to cancel out equivalent expression
2nd - look to cancel out equivalent expression
6y²+9y/12y²
3y(2y+3)/3* 4 y²
3 y(2y+3)/3* 4 y* y
(2y+3)/4y
Final answer : (2y+3)/4y ; y ≠ 0