two numbers have a sum of 40. find the larger number if the product of twice the larger and four more than the smaller is a maximum.

Question

two numbers have a sum of 40. find the larger number if the product of twice the larger and four more than the smaller is a maximum.

Answer 1

Hi Kay,

 

The answer is 12 and 28.  Here is how I got it:

 

n + (2n + 4) = 40

 

3n + 4 = 40

 

3n = 36   n = 12

 

12x2 + 4 =28

 

28 is the larger number.

 

I hope you understood it.  Good luck.