i need some homework help with factoring having with to do algebra they include

x^2-5x-54=0

x^2-3x-4=6

5x^2+16x+3=0

7x^2+37x+10-0

3x^2+5x-2=0

i need some homework help with factoring having with to do algebra they include

x^2-5x-54=0

x^2-3x-4=6

5x^2+16x+3=0

7x^2+37x+10-0

3x^2+5x-2=0

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ax^{2} + bx + c = a(x - x_{1})(x - x_{2}) ; were x_{1,2} = (-b ± √D)/2a

are roots of the equation

ax^{2} + bx + c = 0 and D = b^{2} - 4ac

~~~~~~~~~~

**1.** x^{2} - 5x - 54 = 0 *does not have rational roots.*

**2.** x^{2} - 3x - 4 = 6 ----> x^{2} * - 3*x

(x - 5)(x + 2) = 0 ---> x

x

x

x

5(x + 1/5)(x + 3) = (5x +1)(x + 3) = 0

x

x

7(x + 2/7)(x + 5) = (7x + 2)(x + 5) = 0

Rachel..does your teacher want you to factor these trinomials into bionomials?

example x^{2} - 6x + 5 = ( x - 5)(x - 1)

This this Rachel?

Rachel...very good answers to your inquiry...but might I just add...this is how I help my 9^{th} graders being to answer these kinds of problems. (In words, these kinds of problems are 'factoring a trinomial', which means finding factors, which when multiplied together will equal the trinomial, which usually is a 'binomial'...basically
**(**x + y**) (**x + y**)** = x^{2} + 2xy + y^{2}

With that said, assume the answer will most likely be something like the one above, so begin with writing
**( )( ) **now, we just have to find out what belong inbetween the parenthesis. Next, look at the signs inside the parenthesis, here are the rules(you know these from 6th grade:

Rule 1: if the signs are... ax^{2} + bx + c then the signs are
**( + )( + )**

Rule 2: if the signs are... ax^{2} **+** bx **-** c then the signs are
**( + )( - ) **or Rule 3: if the signs are... ax^{2} + bx - c then the signs are
**( - )( + ) **dependent on if** b > c or b < c **

Rule 4: if the signs are... ax^{2} **-** bx **+** c then the signs are
**( - )( - )**

* Step 1:* Look at the first value

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## Comments

what exactly is your question Rachel? Do you need help factoring those functions?