differential equation. laplace transform

Question

given in series circuit L=1H, R=110ohm, C=0.001F, v=90V. Find the resultant current when the switch is originally open and it is closed for 1s. then it is open again when t=1. use laplace transform. given L(dI/dt)+RI+(1/C)q = v(t)

Answer 1

Current from t=0 to t=1 is:

e^(-10t) - e^(-100t)

 

Link to my work:

http://cl.ly/YPHo   (page 1)

http://cl.ly/YPM3   (page 2)

 

I also solved for specifically t=1, so don't be confused, I was just curious. 

 

The equations for current for all t>0 is also in my work, but that's prly not what the teacher is looking for because the given differential equation won't describe the scenario.