
Byron S. answered 10/08/14
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As an indefinite integral, sin(x)/x is non-integrable. You can expand sin(x/2) using its Taylor series, and integrate that, but you're then dealing with an infinite series. If you're looking for a definite integral, you can use the Taylor series to approximate fairly accurately.
The value of ∫0∞sin(x)/x dx is known to be π/2, so if you have those limits, you can use a u-substitution with u=x/2 and the known integral to find the value.

Byron S.
Have you learned Taylor series yet?
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10/08/14
Andy O.
10/08/14