Differentiate the function. h(t) = t^(1/3) − 3e^t

Question

its a differential equation

Answer 1

Good morning Gerald,

 

For the function

h(t) = t^1/3 - 3e^t,

 

h'(t) = (1/3)t^-2/3 - 3e^t,

 

→ h'(t) = (1/3)/(t^2/3) - 3e^t.

 

*Note:

For the first term I am using the power rule.

For the second term, the derivative of e^t is itself.

 

Thank you for the question, and have a great day!

Michael Ehlers