
Dom V. answered 09/12/18
Tutor
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Cornell Engineering grad specializing in advanced math subjects
Another method:
Let A=ln(a) and B=ln(b)
apx = eApx
bmx = eBmx
apxbmx = eApxeBmx = e(Ap+Bm)x
Let K=(Ap+Bm)
∫eKxdx = (1/K)eKx +C