Inactive Tutor answered 09/12/18
Tutor
New to Wyzant
Another method:
Let A=ln(a) and B=ln(b)
apx = eApx
bmx = eBmx
apxbmx = eApxeBmx = e(Ap+Bm)x
Let K=(Ap+Bm)
∫eKxdx = (1/K)eKx +C
Sid C.
asked 09/04/18Inactive Tutor answered 09/12/18
Mark M. answered 09/04/18
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
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