Mark M. answered 09/03/18
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f'(c) = limx→c {[f(x) - f(c)] / (x-c)}
Let f(x) = 4/(x-4). Then f(-2) = 4/(-6) = -2/3 and f'(x) = -4 / (x-4)2
So, the given limit is equivalent to limx→-2 {[ -f(-2) + f(x)] / (x - (-2)}
= limx→-2{(f(x) - f(-2)) / (x-(-2))}
= f'(-2)
= -4 / (-2-4)2 = -4 / 36 = -1/9