What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?

Question

What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?What is the distance between the points (3, 8) and (-3, 0) in the xy-plane?

Answer 1

So, if we draw a straight line down from (3,8) to the x-axis and then another from there to (-3,0), we see that we have a right triangle with the line from our given points being the hypotenuse.

 

Another way to think of subtraction is "how far apart are two numbers.?" 9 - (-2) = 11 because the two are 11 apart.

 

What's the Pythagorean theorem? a² + b² = c², so if we take the square root of both sides, c = √(a² + b²).

 

Let's put all that together.

 

c = √((3 - (-3))² + (8 - 0)²)

c = √(6² + 8²)

c = √(36 + 64)

c = √100

c = 10