What volume of oxygen gas at STP is required to react with 10g of potassium metal according to the following equation?

Question

2K(s)+O2(g)=K2O(s)

Answer 1

Hello

 

The balanced chemical reaction is:

 

4K (s) + O₂ (g) →2K₂O (s)

 

First convert 10 g of K to moles of O₂ using stoichiometry.  From the above reaction, you can see that 4 moles of K reacts with 1 mole of O₂.  Molar mass of K is 39 g/mol.

 

10 g K x (1 mol K / 39 g K) x (1 mol O₂ / 4 mol K) = 0.0641 mol O₂

 

1 mole of O₂ at STP occupies a volume of 22.4 L.  Therefore, 0.0641 mol of O₂ will occupy a volume of:

 

0.0641 mol O₂ x (22.4 L / 1 mol O₂) = 1.44 L

Answer 2

answer removed - wrong mole ratio!