Anonymous 1.

asked • 08/21/18

According to the ideal gas law

If the amount of a gas is doubled and the absolute temperature of the gas is also doubled while the volume remains unchanged, then the pressure of a gas should
 
a) Increase by two times
b) Decrease by two times
c) Increase by four times
d) Increase by eight times
e) No change; the effects cancel each other out.
 
Is the answer a)? I'm unsure

Arturo O.

If you have trouble understanding this, just plug the new numbers into the ideal gas law, as in my solution below, and solve for the new pressure.  It will be more clear.
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08/21/18

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Arturo O. answered • 08/21/18

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PV = nRT
 
P = nRT/V
 
Replace n with 2n, and replace T with 2T; V does not change.
 
P' = (2n)R(2T)/V = 4nRT/V = 4P
 
Pressure increases by a factor of 4.
 
 
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Tyler V.

Thank you. So the answer is it increase by four times or no change; the affects cancel each other out? 
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08/21/18

Arturo O.

No.  For the conditions stated in the problem, the pressure increases by a factor of 4.  That is the result of the math.  Answer (c) is correct.
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08/21/18

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