
Emilee F. answered 07/23/18
Tutor
New to Wyzant
10+ Years of Tutoring Experience, Specializing in Math & Science
If q(x)=x+b
and r(x)= x+d
Then q(r(x)) = (x+d)+b
and r(x)= x+d
Then q(r(x)) = (x+d)+b
Saying this outloud always helps. You're trying to find Q of (R of -5), so you need to find R of -5 first.
(Q*R)(-5):
R(-5) = -3*(-5) - 4
R(-5) = 15 - 4
R(-5) = 11
R(-5) = 15 - 4
R(-5) = 11
Now plug 11 into the Q function:
Q(X)=3X+3
Q(11) = 3*11 + 3
Q(11) = 33 + 3
Q(11) = 36
Q(11) = 33 + 3
Q(11) = 36
So, (Q(R(-5)) = 36
(R*Q)(-5):
Now you're finding "R of (Q of -5)" so first you must calculate Q(-5).
Now you're finding "R of (Q of -5)" so first you must calculate Q(-5).
Q(X)=3X+3
Q(-5) = 3*(-5) + 3
Q(-5) = -15 + 3
Q(-5) = -12
Q(-5) = -15 + 3
Q(-5) = -12
Now, plug -12 into R(X):
R(X)=-3X-4
R(-12) = -3(-12) - 4
R(-12) = 36 - 4
R(-12) = 32
R(X)=-3X-4
R(-12) = -3(-12) - 4
R(-12) = 36 - 4
R(-12) = 32
So, R(Q(-5)) = 32