Yohan C. answered 09/21/14
Tutor
4
(1)
Math Tutor (up to Calculus) (not Statistics and Finite)
Let's look at (Ax2 +Bx + C). Since A is 3, it will look something like this:
(3x )(x ). To find out those missing numbers, we have to look at C value: -6.
Since C is negative, you know that one of them must be negative. It is either 6&1 or 3&2.
How to find which one fits that? look at each binomials: (3x ) and (x ). If you use 6&1, the middle term will be either +17, -17 (if 6 is with x and 1 is with 3x)) or +9, -9 (if 6 is with 3x and 1 is with x) so this will not work.
3&2. As you use 3 and 2, you can see that 3 & 3 makes 9 and 1 & 2 makes 2 to make 7. How to put them in right place? since 3 has to be multiplied, 3 must go with x and 2 must go with 3x. So it will look something like this:
(3x 2) (x 3). How to figure out the signs? (remember, one of them must be negative because C is negative) compare the 3x * 3 and 2 * x. Since middle term is negative, the bigger one gets - sign. So, how to make -7x between 9x & 2x? -9x + 2x. So, final answer look like this:
(3x+2) (x-3).
That 3 has to be outside because it has to be multiplied. If the 3 stayed with 3x or stayed inside, it becomes one term. If terms and numbers wants to be multiplied, they must be separated or it will be known as one term.
A lot of people will "grouping method" to be easy but I rather go through trial and error because it builds more depths and experience. And "grouping method" catch people off guard if big number comes up.
Good luck.
Yohan C.
09/21/14