Kenneth S. answered 05/31/18
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
It appears that you are dealing with an arithmetic sequence.
a100 = a1 + 99d
307 = 15 + 99d
d = 2.949494... which equals 2 94/99 or 292/99, a very unusual constant difference.
But you can find the sum of n=100 terms by the formula Sn = (n/2)(a1 + an).
Blue T.
05/31/18